Gujarati
Hindi
3-1.Vectors
easy

Projection of vector $\vec A$ on $\vec B$ is

A

$\vec A.\vec B$

B

$\vec A.\hat B$

C

$\vec B \times \vec A$

D

$\hat B.\hat A$

Solution

$A\,\cos \,\theta  = \frac{{\vec A.\vec B}}{{\left| {\vec B} \right|}} = \vec A.\hat B$

Standard 11
Physics

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